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3x^2-13x-34=0
a = 3; b = -13; c = -34;
Δ = b2-4ac
Δ = -132-4·3·(-34)
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{577}}{2*3}=\frac{13-\sqrt{577}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{577}}{2*3}=\frac{13+\sqrt{577}}{6} $
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